Match List-I with List-II. List-I Electronic configuration of neutral atom (where n=2) List-II 1^ st Ionization Energy (kJ mol^ -1 ) A. ns^2 I. 2080 B. ns^2np^1 II. 899 C. ns^2np^3 III. 800 D. ns^2np^6 IV. 1402 Choose the correct answer from the options given below:
A. A-II, B-III, C-IV, D-I
Given n=2, the electronic configurations correspond to elements of the second period. A. ns^2 2s^2 is Beryllium (Be). B. ns^2np^1 2s^2 2p^1 is Boron (B). C. ns^2np^3 2s^2 2p^3 is Nitrogen (N). D. ns^2np^6 2s^2 2p^6 is Neon (Ne). The first ionization energy generally increases across a period from left to right. However, Beryllium has a higher ionization energy than Boron due to the stable fully-filled 2s subshell. Nitrogen has a high ionization energy due to its stable half-filled 2p subshell. Neon, being a noble gas, has the highest ionization energy. The order of first ionization energy is B Arranging the given values in increasing order: 800 Thus, the matching is: A. Be 899 (II) B. B 800 (III) C. N 1402 (IV) D. Ne 2080 (I) This corresponds to A-II, B-III, C-IV, D-I. Answer: A-II, B-III, C-IV, D-I
Related: Chemistry — Classification of Elements and Periodicity in Properties · All PYQ Banks