Given below are two statements: Statement I: The correct order of electronegativity of fluorine, oxygen and nitrogen is F > O > N. Statement II: The oxidation state of oxygen in OF_2 is +2 and in Na_2O is -2. In the light of the above statements, choose the correct answer from the options given below
A. Both Statement I and Statement II are true
Electronegativity increases across a period from left to right. Nitrogen, oxygen, and fluorine belong to group 15, 16, and 17 respectively in the second period. Thus, the correct order of electronegativity is F > O > N. Statement I is true. In OF_2, fluorine is more electronegative than oxygen and always exhibits an oxidation state of -1. Let the oxidation state of oxygen be x. Then x + 2(-1) = 0 x = +2. In Na_2O, sodium is an alkali metal and exhibits an oxidation state of +1. Let the oxidation state of oxygen be y. Then 2(+1) + y = 0 y = -2. Statement II is also true. Both Statement I and Statement II are true. Answer: Both Statement I and Statement II are true
Related: Chemistry — Classification of Elements and Periodicity in Properties · All PYQ Banks