Question
Elements X and Y belong to Group 15. The difference between the electronegativity values of ' X ' and phosphorus is higher than that of the difference between phosphorus and ' Y '. ' X ' \& ' Y ' are respectively
JEE Main
Chemistry
Classification of Elements and Periodicity in Properties
2026
JEE Main 2026 (23 January Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. N & As
- B. As ~\&~ Sb
- C. Bi & N
- D. As & Bi
Answer
A. N & As
Step-by-step solution
Group 15 elements have electronegativity values (Pauling scale): N = 3.04, P = 2.19, As = 2.18, Sb = 2.05, Bi = 2.02. The condition requires: |EN(X) - EN(P)| > |EN(P) - EN(Y)|. (1) N and As: |3.04 - 2.19| = 0.85 and |2.19 - 2.18| = 0.01. Since 0.85 > 0.01, the condition is satisfied. (2) As and Sb: |2.18 - 2.19| = 0.01 and |2.19 - 2.05| = 0.14. Since 0.01 (3) Bi and N: |2.02 - 2.19| = 0.17 and |2.19 - 3.04| = 0.85. Since 0.17 (4) As and Bi: |2.18 - 2.19| = 0.01 and |2.19 - 2.02| = 0.17. Since 0.01 < 0.17, it fails.
Related: Chemistry — Classification of Elements and Periodicity in Properties · All PYQ Banks