Question
An excess of AgNO_3 is added to 100 mL of a 0.05 M solution of tetraaquadichloridochromium (III) chloride. The number of moles of AgCl precipitated will be __________ 10^ -3 . (Nearest integer)
JEE Main
Chemistry
Coordination Compounds
2026
JEE Main 2026 (06 April Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
The formula of tetraaquadichloridochromium (III) chloride is [Cr(H_2O)_4Cl_2]Cl. In this complex, there is one ionizable chloride ion present outside the coordination sphere. The dissociation reaction is: [Cr(H_2O)_4Cl_2]Cl [Cr(H_2O)_4Cl_2]^+ + Cl^- Number of moles of the complex = M V = 0.05 100 1000 = 0.005 moles. Since one mole of the complex yields one mole of chloride ions, the number of moles of Cl^- ions produced is 0.005 moles. When excess AgNO_3 is added, the chloride ions precipitate as AgCl: Ag^+ + Cl^- AgCl Number of moles of AgCl precipitated = 0.005 = 5 10^ -3 moles. The value is 5. Answer: 5
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