Match the LIST-I with LIST-II List-I Electronic configuration of tetrahedral metal ion List-II Crystal Field Stabilization Energy ( _t) A. d^2 I. -0.6 B. d^4 II. -0.8 C. d^6 III. -1.2 D. d^8 IV. -0.4 Choose the correct answer from the options given below:
C. A-III, B-IV, C-I, D-II
In a tetrahedral crystal field, the d-orbitals split into a lower energy e set and a higher energy t_2 set. The energy of an electron in the e orbital is -0.6 _t and in the t_2 orbital is +0.4 _t. Since _t is generally small, tetrahedral complexes form high-spin configurations. The Crystal Field Stabilization Energy (CFSE) is given by: CFSE = (-0.6 n_e + 0.4 n_ t_2 ) _t For d^2: The configuration is e^2 t_2^0. CFSE = 2 (-0.6) + 0 = -1.2 _t (A III) For d^4: The configuration is e^2 t_2^2. CFSE = 2 (-0.6) + 2 (0.4) = -1.2 + 0.8 = -0.4 _t (B IV) For d^6: The configuration is e^3 t_2^3. CFSE = 3 (-0.6) + 3 (0.4) = -1.8 + 1.2 = -0.6 _t (C I) For d^8: The configuration is e^4 t_2^4. CFSE = 4 (-0.6) + 4 (0.4) = -2.4 + 1.6 = -0.8 _t (D II) Therefore, the correct match is A-III, B-IV, C-I, D-II. Answer: A-III, B-IV, C-I, D-II
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