Match the LIST-I with LIST-II List-I Complex ion List-II Calculated spin only magnetic moment (BM) A. [Cr(H_2O)_6]^ 2+ I. 3.87 B. [Co(H_2O)_6]^ 2+ II. 5.92 C. [Cu(H_2O)_6]^ 2+ III. 4.90 D. [Mn(H_2O)_6]^ 2+ IV. 1.73 Choose the correct answer from the options given below:
D. A-III, B-I, C-IV, D-II
The spin-only magnetic moment is given by the formula = n(n+2) BM, where n is the number of unpaired electrons. A. [Cr(H_2O)_6]^ 2+ : Chromium is in the +2 oxidation state. The electronic configuration of Cr^ 2+ is [Ar] 3d^4. Since H_2O is a weak field ligand, no pairing occurs. The number of unpaired electrons is n = 4. = 4(4+2) = 24 4.90 BM. (A III) B. [Co(H_2O)_6]^ 2+ : Cobalt is in the +2 oxidation state. The electronic configuration of Co^ 2+ is [Ar] 3d^7. With H_2O as a weak field ligand, the configuration is t_ 2g ^5 e_g^2. The number of unpaired electrons is n = 3. = 3(3+2) = 15 3.87 BM. (B I) C. [Cu(H_2O)_6]^ 2+ : Copper is in the +2 oxidation state. The electronic configuration of Cu^ 2+ is [Ar] 3d^9. The number of unpaired electrons is n = 1. = 1(1+2) = 3 1.73 BM. (C IV) D. [Mn(H_2O)_6]^ 2+ : Manganese is in the +2 oxidation state. The electronic configuration of Mn^ 2+ is [Ar] 3d^5. With H_2O as a weak field ligand, the configuration is t_ 2g ^3 e_g^2. The number of unpaired electrons is n = 5. = 5(5+2) = 35 5.92 BM. (D II) The correct matching is A-III, B-I, C-IV, D-II. Answer: A-III, B-I, C-IV, D-II
Related: Chemistry — Coordination Compounds · All PYQ Banks