5.33 g of CrCl_3 6H_2O, which is a 1 : 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with AgNO_3 results in 8.61 g of AgCl. The ratio of moles of complex reacted and moles of AgCl formed is _______ 10^ -2 . (Nearest integer) [Molar mass in g mol^ -1 Cr : 52, Ag : 108, Cl : 35.5, H : 1, O : 16]
A. A
Molar mass of CrCl_3 6H_2O = 52 + 3 35.5 + 6 18 = 266.5 g mol ^ -1 Moles of complex reacted = 5.33 266.5 = 0.02 mol Since the complex is a 1:3 electrolyte, it dissociates to give one complex cation and three chloride anions. Its formula is [Cr(H_2O)_6]Cl_3. When passed through a cation exchanger, the complex cation is exchanged, and the chloride ions pass into the eluted solution. Molar mass of AgCl = 108 + 35.5 = 143.5 g mol ^ -1 Moles of AgCl formed = 8.61 143.5 = 0.06 mol The ratio of moles of complex reacted to moles of AgCl formed is: Ratio = 0.02 0.06 = 1 3 = 0.3333... This can be written as 33.33 10^ -2 . Rounding to the nearest integer, we get 33. Answer: 33
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