JEE Main
Chemistry
Coordination Compounds
2026
JEE Main 2026 (28 January Shift 1)
JEE Main Chemistry Question (2026) — Solution
Question
X is the number of geometrical isomers exhibited by [ Pt ( NH _ 3 ) ( H _ 2 O ) BrCl ]. Y is the number of optically inactive isomer(s) exhibited by [ CrCl _ 2 ( ox )_ 2 ]^ 3- Z is the number of geometrical isomers exhibited by [ Co ( NH _ 3 )_ 3 ( NO _ 2 )_ 3 ]. The value of X + Y + Z is \_\_\_\_.
Step-by-step solution
For [Pt(NH_3)(H_2O)BrCl] with square planar geometry and four different ligands, geometrical isomerism arises from different positional arrangements: X = 3. For [CrCl_2(ox)_2]^ 3- , the trans isomer is optically inactive (meso compound) while cis is optically active, giving Y = 1. For [Co(NH_3)_3(NO_2)_3] in octahedral geometry, facial (fac) and meridional (mer) isomers are possible: Z = 2. Therefore, X + Y + Z = 3 + 1 + 2 = 6
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