Given below are two statements: Statement I : The number of paramagnetic species among [ CoF _ 6 ]^ 3- , [ TiF _ 6 ]^ 3- , V _ 2 O _ 5 and [ Fe ( CN )_ 6 ]^ 3- is 3. Statement II : K _ 4 [ Fe ( CN )_ 6 ] In the light of the above statements, choose the correct answer from the options given below
A. Both Statement I and Statement II are true
Statement I: Analysis of paramagnetic species. 1. [CoF_6]^ 3- : Co^ 3+ is 3d^6. F^- is a weak field ligand (WFL), so configuration is t_ 2g ^4 e_g^2. Unpaired electrons (n) = 4. Paramagnetic. 2. [TiF_6]^ 3- : Ti^ 3+ is 3d^1. n = 1. Paramagnetic. 3. V_2O_5: V^ 5+ is 3d^0. n = 0. Diamagnetic. 4. [Fe(CN)_6]^ 3- : Fe^ 3+ is 3d^5. CN^- is a strong field ligand (SFL), so configuration is t_ 2g ^5 e_g^0. n = 1. Paramagnetic. Total paramagnetic species = 3. Statement I is true. Statement II: Analysis of unpaired electrons. 1. K_4[Fe(CN)_6]: Fe^ 2+ (3d^6) with SFL t_ 2g ^6 e_g^0, n = 0. 2. K_3[Fe(CN)_6]: Fe^ 3+ (3d^5) with SFL t_ 2g ^5 e_g^0, n = 1. 3. [Fe(H_2O)_6]SO_4 H_2O: Fe^ 2+ (3d^6) with WFL t_ 2g ^4 e_g^2, n = 4. 4. [Fe(H_2O)_6]Cl_3: Fe^ 3+ (3d^5) with WFL t_ 2g ^3 e_g^2, n = 5. Order of n: 0 Both statements are true.
Related: Chemistry — Coordination Compounds · All PYQ Banks