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JEE Main Chemistry d and f Block Elements 2026 JEE Main 2026 (28 January Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

Consider the following statements about manganate and permanganate ions. Identify the correct statements. A. The geometry of both manganate and permanganate ions is tetrahedral. B. The oxidation states of Mn in manganate and permanganate are +7 and +6, respectively. C. Oxidation of Mn (II) salt by peroxodisulphate gives manganate ion as the final product. D. Manganate ion is paramagnetic and permanganate ions is diamagnetic. E. Acidified permanganate ion reduces oxalate, nitrite and iodide ions. Choose the correct answer from the options given below :

Options

  1. A. A, C and D Only
  2. B. A and D Only
  3. C. A, D and E Only
  4. D. A, B and C Only

Answer

B. A and D Only

Step-by-step solution

Manganate ion → MnO _4^ 2- Permanganate ion → MnO _4^ - (A) Both are tetrahedral (d^3s hybridisation) TRUE (B) MnO _4^ - has Mn in +7 oxidation state; MnO _4^ 2- has Mn in +6 oxidation state. The statement says +7 for manganate and +6 for permanganate, which is reversed. FALSE (C) Oxidation of Mn ^ 2+ by peroxodisulphate ( S _2 O _8^ 2- ) gives permanganate ion ( MnO _4^ - ), not manganate ion. FALSE (D) MnO _4^ - is diamagnetic; MnO _4^ 2- is paramagnetic. TRUE (E) Acidified permanganate ion oxidises (not reduces) oxalate, nitrite and iodide ions. FALSE Correct statements: A and D only.

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