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JEE Main Chemistry Electrochemistry 2026 JEE Main 2026 (28 January Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

For strong electrolyte _ m increases slowly with dilution and can be represented by the equation _ m = _ m ^ - Ac ^ 1 / 2 Molar conductivity values of the solutions of strong electrolyte AB at 18^ C are given below : \( array |l|c|c|c|c| c \;[ mol\,L^ -1 ] & 0.04 & 0.09 & 0.16 & 0.25 \\ _ m \;[ S\,cm^ 2 \,mol^ -1 ] & 96.1 & 95.7 & 95.3 & 94.9 \\ array \) The value of constant A based on the above data [ . in . S cm ^ 2 ~mol ^ -1 /( mol / L )^ 1 / 2 ] unit is \_\_\_\_.

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

The equation _m = _m^0 - Ac^ 1/2 is linear in c^ 1/2 . Taking two data points: (c=0.04, c =0.2, _m=96.1) and (c=0.25, c =0.5, _m=94.9). Slope = 94.9 - 96.1 0.5 - 0.2 = -1.2 0.3 = -4.0 Since slope = -A, the constant A = 4 S cm² mol⁻¹/(mol/L)^(1/2)

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