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JEE Main Chemistry Electrochemistry 2026 JEE Main 2026 (21 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

The pH and conductance of a weak acid (HX) was found to be 5 and 4 10^ -5 ~S , respectively. The conductance was measured under standard condition using a cell where the electrode plates having a surface area of 1 ~cm ^ 2 were at a distance of 15 cm apart. The value of the limiting molar conductivity is \_\_\_\_ S m ^ 2 ~mol ^ -1 . (nearest integer) (Given : degree of dissociation of the weak acid ( ) 1)

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

Given: pH = 5, so [H^+] = 10^ -5 M; G = 4 10^ -5 S; A = 1 cm²; l = 15 cm Cell constant = l/A = 15 cm⁻¹ Specific conductivity: = G (l/A) = 4 10^ -5 15 = 6 10^ -4 S/cm For weak acid HX: [H^+] = C = 10^ -5 M Using = C °_m 1000 °_m = 1000 C = 1000 6 10^ -4 10^ -5 = 6 10^4 S cm² mol⁻¹ Converting: °_m = 6 10^4 10^ -4 = 6 S m² mol⁻¹

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