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JEE Main Chemistry General Organic Chemistry 2026 JEE Main 2026 (06 April Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

Given below are two statements : Statement I : A mixture of C_ 12 H_ 22 O_ 11 (sugar) and NaCl can be separated by dissolving sugar in alcohol, due to differential solubility. Statement II : Rose essence from rose petals is seperated by steam distillation due to its high volatility and insolubility in H_2O. In the light of the above statements, choose the correct answer from the options given below :

Options

  1. A. Both Statement I and Statement II are true
  2. B. Both Statement I and Statement II are false
  3. C. Statement I is true but Statement II is false
  4. D. Statement I is false but Statement II is true

Answer

A. Both Statement I and Statement II are true

Step-by-step solution

Statement I : Sugar ( C _ 12 H _ 22 O _ 11 ) is soluble in alcohol, whereas sodium chloride ( NaCl ) is insoluble in alcohol. Therefore, a mixture of sugar and salt can be separated based on their differential solubility in alcohol. This statement is true. Statement II : Steam distillation is used to separate and purify organic compounds that are steam volatile and immiscible (insoluble) in water. Rose essence (essential oil) from rose petals possesses these properties, making steam distillation the appropriate method for its extraction. This statement is also true. Therefore, both Statement I and Statement II are true. Answer: Both Statement I and Statement II are true

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