Question
In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO_4. The percentage of sulphur in the substance is _____ %. (Given molar mass in g mol^ -1 S : 32, BaSO_4 : 233)
JEE Main
Chemistry
General Organic Chemistry
2026
JEE Main 2026 (05 April Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
Mass of the organic compound, W = 0.2 g Mass of BaSO _4 formed, m = 0.6 g Molar mass of BaSO _4 = 233 g mol ^ -1 Molar mass of S = 32 g mol ^ -1 The percentage of sulphur in the organic compound is given by the formula: \% S = 32 233 m W 100 Substituting the given values: \% S = 32 233 0.6 0.2 100 \% S = 32 233 3 100 \% S = 9600 233 41.20\% Rounding off to the nearest integer, the percentage of sulphur is 41. Answer: 41
Related: Chemistry — General Organic Chemistry · All PYQ Banks