Question
In sulphur estimation, 2.0 10^ -3 mol of an organic compound (X) (molar mass 76 g mol^ -1 ) gave 0.4813 g of barium sulphate (molar mass 233 g mol^ -1 ). The percentage of sulphur in the compound (X) is ______ 10^ -1 % (Nearest integer)
JEE Main
Chemistry
General Organic Chemistry
2026
JEE Main 2026 (04 April Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
Mass of the organic compound (X) can be calculated as: Mass of X = Moles Molar mass Mass of X = 2.0 10^ -3 mol 76 g mol ^ -1 = 0.152 g In the Carius method for sulphur estimation, the mass of sulphur in the given mass of BaSO _4 is: Mass of S = 32 233 Mass of BaSO _4 Mass of S = 32 233 0.4813 g 0.0661 g The percentage of sulphur in the organic compound is given by: \% of S = Mass of S Mass of X 100 \% of S = 0.0661 0.152 100 43.487 \% To express this in the requested format: 43.487 \% = 434.87 10^ -1 \% Rounding to the nearest integer, we get 435. Answer: 435
Related: Chemistry — General Organic Chemistry · All PYQ Banks