Question
In Carius method 0.2425 g of an organic compound gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is
JEE Main
Chemistry
General Organic Chemistry
2026
JEE Main 2026 (23 January Shift 2)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 34.79 \%
- B. 37.57 \%
- C. 87.65 \%
- D. 53.58 \%
Answer
D. 53.58 \%
Step-by-step solution
In Carius method, chlorine is converted to AgCl. Molar mass of AgCl = 143.5 g/mol. Moles of AgCl formed = 0.5253 / 143.5 = 0.003661 mol. Since each AgCl contains one Cl atom, moles of Cl = 0.003661 mol. Mass of Cl = 0.003661 × 35.5 = 0.1300 g. Percentage of Cl = (0.1300 / 0.2425) × 100 = 53.58%.
Related: Chemistry — General Organic Chemistry · All PYQ Banks