Question
In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 ~g ~mol ^ -1 ). Molar mass of barium sulphate is 233 ~g ~mol ^ -1 .
JEE Main
Chemistry
General Organic Chemistry
2026
JEE Main 2026 (21 January Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 10.30%
- B. 16.48%
- C. 21.97%
- D. 4.55 \%
Answer
C. 21.97%
Step-by-step solution
In Carius method, sulfur is converted to BaSO_4. Each mole of BaSO_4 contains 1 mole of S. Mass of S = 32 233 1.2 = 0.1648 g Percentage of S = 0.1648 0.75 100 = 21.97\%
Related: Chemistry — General Organic Chemistry · All PYQ Banks