RMgI when treated with ice cold water liberated a gas which occupied 1.4 dm ^3/ g at STP. The gas produced is further reacted with iodine in presence of HIO_3 to give compound (X). Compound (X) in presence of Na and dry ether produced compound (Y). Molar mass of compound (Y) is _______ g mol ^ -1 . (Nearest integer)
A. A
The reaction of Grignard reagent with water yields an alkane: RMgI + H_2O RH + Mg(OH)I Given that 1 g of the gas RH occupies 1.4 dm ^3 at STP, we can find its molar mass. Using the standard molar volume at STP (22.4 dm ^3): Molar mass of RH = 22.4 dm ^3 mol ^ -1 1.4 dm ^3 g ^ -1 = 16 g mol ^ -1 The alkane with a molar mass of 16 g mol ^ -1 is methane (CH_4). Methane reacts with iodine in the presence of an oxidizing agent like HIO_3 (which prevents the backward reaction by consuming the formed HI) to give methyl iodide: CH_4 + I_2 HIO_3 CH_3I + HI Thus, compound (X) is methyl iodide (CH_3I). Compound (X) undergoes the Wurtz reaction when treated with sodium and dry ether to form a higher alkane: 2CH_3I + 2Na dry ether CH_3-CH_3 + 2NaI Compound (Y) is ethane (C_2H_6). The molar mass of ethane (C_2H_6) is: 2 12 + 6 1 = 30 g mol ^ -1 Answer: 30
Related: Chemistry — Haloalkanes and Haloarenes · All PYQ Banks