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JEE Main Chemistry Haloalkanes and Haloarenes 2026 JEE Main 2026 (04 April Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

Match the LIST-I with LIST-II List-I (Reaction) List-II (Mechanism) A. Williamson Synthesis I. Electrophilic addition B. Friedel Craft Reaction II. Free radical substitution C. Bromination of vinyl benzene III. Nucleophilic substitution D. Chlorination of toluene in light IV. Electrophilic substitution Choose the correct answer from the options given below:

Options

  1. A. A-III, B-I, C-II, D-IV
  2. B. A-III, B-IV, C-II, D-I
  3. C. A-III, B-IV, C-I, D-II
  4. D. A-I, B-III, C-IV, D-II

Answer

C. A-III, B-IV, C-I, D-II

Step-by-step solution

Williamson synthesis involves the reaction of an alkyl halide with a sodium alkoxide to form an ether, which proceeds via a nucleophilic substitution (S_N2) mechanism. Thus, A matches with III. Friedel-Crafts reaction involves the alkylation or acylation of an aromatic ring in the presence of a Lewis acid catalyst, which proceeds via an electrophilic substitution mechanism. Thus, B matches with IV. Bromination of vinyl benzene (styrene) involves the addition of bromine across the carbon-carbon double bond, which proceeds via an electrophilic addition mechanism. Thus, C matches with I. Chlorination of toluene in the presence of sunlight (or UV light) involves the substitution of hydrogen atoms in the methyl group by chlorine, which proceeds via a free radical substitution mechanism. Thus, D matches with II. The correct matching is A-III, B-IV, C-I, D-II. Answer: A-III, B-IV, C-I, D-II

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