R_f value for 2-methylpropene in a solvent system (Ethyl acetate + ether) is 0.42. 2-methylpropene is treated with dilute H _2 SO _4 to give major organic product (X). R_f value for (X) in the same solvent system under identical condition will be:
D. 0.12
2-methylpropene reacts with dilute H_2SO_4 to undergo hydration, forming tert-butyl alcohol as the major product (X). The reaction is: CH_2=C(CH_3)_2 dil. H_2SO_4 (CH_3)_3C-OH Product (X) is an alcohol, which is significantly more polar than the starting alkene due to the presence of the -OH group. In normal phase chromatography, the stationary phase (such as silica gel) is highly polar. The polar -OH group forms strong hydrogen bonds with the stationary phase, causing the alcohol to be adsorbed more strongly than the non-polar alkene. Consequently, the alcohol travels a shorter distance along the chromatography plate, resulting in a lower R_f value compared to the alkene. Since the R_f value of 2-methylpropene is 0.42, the R_f value of product (X) must be less than 0.42. Among the given choices, only 0.12 satisfies this condition. Answer: 0.12
Related: Chemistry — Hydrocarbons · All PYQ Banks