The mass of iron converted into Fe_3O_4 by the action of 18 g of steam is : (Given : Molar mass of H, O and Fe are 1, 16 and 56 g mol^ -1 respectively) Assume iron is present in excess :

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Correct answer: D. 42 g

The balanced chemical equation for the reaction of iron with steam is: 3Fe + 4H_2O Fe_3O_4 + 4H_2 Molar mass of H_2O = 2 1 + 16 = 18 g mol ^ -1 Number of moles of steam (H_2O) given = 18 18 = 1 mol From the balanced equation, 4 moles of H_2O react with 3 moles of Fe. Therefore, 1 mole of H_2O will react with 3 4 moles of Fe. Mass of iron reacted = Moles of Fe Molar mass of Fe Mass of iron = 3 4 56 = 3 14 = 42 g Answer: 42 g

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