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JEE Main Chemistry p Block Elements (Group 15, 16, 17 & 18) 2026 JEE Main 2026 (04 April Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Given below are two statements: Statement I: The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in SO_2 is -2 and in OF_2 it is +2. Statement II: The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity. In the light of the above statements, choose the correct answer from the options given below

Options

  1. A. Both Statement I and Statement II are true
  2. B. Both Statement I and Statement II are false
  3. C. Statement I is true but Statement II is false
  4. D. Statement I is false but Statement II is true

Answer

A. Both Statement I and Statement II are true

Step-by-step solution

Statement I: The electronic configuration of oxygen is 1s^ 2 2s^ 2 2p^ 4 . Due to the absence of d-orbitals, its maximum covalency is limited to four (using one 2s and three 2p orbitals). Its covalency is generally two, but it can exceed two and go up to four in certain compounds. In SO_2, oxygen is more electronegative than sulphur, so its oxidation state is -2. In OF_2, fluorine is more electronegative than oxygen, so the oxidation state of oxygen is +2. Thus, Statement I is true. Statement II: Oxygen differs from the rest of the group 16 elements due to its small atomic size, high electronegativity, and the absence of d-orbitals in its valence shell. This leads to its anomalous behaviour, such as the ability to form strong hydrogen bonds and p -p multiple bonds. Thus, Statement II is true. Both Statement I and Statement II are true. Answer: Both Statement I and Statement II are true

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