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JEE Main Chemistry p Block Elements (Group 15, 16, 17 & 18) 2026 JEE Main 2026 (22 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

A ' p '-block element ( E ) and hydrogen form a binary cation ( EH _ x )^ + , while EH _ 3 on treatment with K _ 2 HgI _ 4 in alkaline medium gives a precipitate of basic mercury(II)amido-iodine. Given below are first ionisation enthalpy values ( kJ mol ^ -1 ) for first element each from group 13, 14, 15 and 16. Identify the correct first ionisation enthalpy value for element E.

Options

  1. A. 1312
  2. B. 1402
  3. C. 1086
  4. D. 801

Answer

B. 1402

Step-by-step solution

The p-block element E forms a binary cation (EH_x)^+ with hydrogen and produces a basic mercury(II) amido-iodide precipitate with K_2HgI_4 in alkaline medium. This behavior is characteristic of ammonia (NH₃), which forms the ammonium ion (NH_4)^+ and reacts with Nessler's reagent (K_2HgI_4) to form a characteristic brown/yellow precipitate. Therefore, E is Nitrogen (N), a Group 15 p-block element with electronic configuration 1s^2 2s^2 2p^3. Nitrogen has a notably high first ionization enthalpy compared to other group 15 elements due to: Small atomic radius High effective nuclear charge Stable half-filled p³ subshell configuration The first ionization enthalpy of nitrogen is 1402 kJ/mol.

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