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JEE Main Chemistry Practical Chemistry 2026 JEE Main 2026 (04 April Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

Among Fe^ 3+ , Pb^ 2+ , Cu^ 2+ and Mn^ 2+ , identify the one that gets precipitated out while passing H_2S in presence of NH_4OH as group reagent. The highest possible oxidation state of the corresponding metal is

Options

  1. A. +3
  2. B. +4
  3. C. +2
  4. D. +7

Answer

D. +7

Step-by-step solution

The group reagent H_2S in the presence of NH_4OH is used for the precipitation of Group IV cations in qualitative analysis. Among the given ions, Mn^ 2+ belongs to Group IV and is precipitated as MnS. Pb^ 2+ and Cu^ 2+ belong to Group II and are precipitated by H_2S in an acidic medium. Fe^ 3+ belongs to Group III and is precipitated as Fe(OH)_3 by NH_4OH in the presence of NH_4Cl. The metal corresponding to the precipitated ion is Manganese (Mn). The electronic configuration of Mn is [Ar] 3d^5 4s^2. By losing all its valence electrons, it can exhibit a maximum oxidation state of +7 (for example, in KMnO_4). Answer: +7

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