A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is \_\_\_\_. (Given Molar mass in g mol ^ -1 ~S : 32, BaSO _ 4 : 233)

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Correct answer: C. 21.05 %

Given: Mass of organic compound = 0.314 g, Mass of BaSO _4 obtained = 0.4813 g. \%S = 32 233 0.4813 0.314 100 = 32 0.4813 100 233 0.314 = 1540.16 73.162 = 21.05\%

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