500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO _ 4 solution in basic medium. The liberated iodine was titrated with standard 0.1 M Na _ 2 ~S _ 2 O _ 3 solution in the presence of starch indicator till the blue color disappeared. The volume (in L) of Na _ 2 ~S _ 2 O _ 3 consumed is \_

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500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO _ 4 solution in basic medium. The liberated iodine was titrated with standard 0.1 M Na _ 2 ~S _ 2 O _ 3 solution in the presence of starch indicator till the blue color disappeared. The volume (in L) of Na _ 2 ~S _ 2 O _ 3 consumed is \_\_\_\_. (Nearest integer)

Quantrex Academy · Accepted Answer

Correct answer: A. A

MnO_4^- + I^- MnO_2 + I_2 I_2 + S_2O_3^ 2- S_4O_6^ 2- + I^- gram eq of KMnO_4 = gram eq of Na_2S_2O_3 0.2 500 1000 3 = 0.1 V 1 V = 3 L

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