Quantrex Academy · Free JEE Main PYQ solutions
JEE Main Chemistry Solutions 2026 JEE Main 2026 (21 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQ _ 2 . When 1 g of PQ is dissolved in 50 g of solvent ^ A ^ , T _ b was 1.176 K while when 1 g of PQ _ 2 is dissolved in 50 g of solvent ^ A ^ , T _ b was 0.689 K. ( K _ b of ' A ^ =5 ~K ~kg ~mol ^ -1 ). The molar masses of elements P and Q (in g mol ^ -1 ) respectively, are :

Options

  1. A. 70,110
  2. B. 65,145
  3. C. 25,60
  4. D. 60,25

Answer

C. 25,60

Step-by-step solution

Using T_b = K_b w M 1000 W For PQ: 1.176 = 5 1 M_ PQ 1000 50 = 100 M_ PQ M_ PQ = 100 1.176 = 85 g/mol For PQ_2: 0.689 = 100 M_ PQ_2 M_ PQ_2 = 100 0.689 = 145 g/mol P + Q = 85 ... (i) P + 2Q = 145 ... (ii) Subtracting: Q = 60 g/mol From (i): P = 85 - 60 = 25 g/mol

Practice more on Quantrex App →

Related: Chemistry — Solutions · All PYQ Banks