How many grams of residue is obtained by heating 2.76 g of silver carbonate? (Given: Molar mass of C, O and Ag are 12, 16 and 108 g mol^ -1 respectively)

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Correct answer: B. 2.16 g

Molar mass of Ag_2CO_3 = 2 108 + 12 + 3 16 = 276 g mol^ -1 Number of moles of Ag_2CO_3 = 2.76 276 = 0.01 mol The decomposition reaction of silver carbonate on heating is: Ag_2CO_3(s) 2Ag(s) + CO_2(g) + 1 2 O_2(g) From the stoichiometry of the reaction, 1 mole of Ag_2CO_3 gives 2 moles of Ag as residue. Number of moles of Ag formed = 2 0.01 = 0.02 mol Mass of Ag residue = 0.02 108 = 2.16 g Answer: 2.16 g

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