Question
14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K. Which of the following statements is incorrect? [Given : Molar mass in g mol ^ -1 of Ca -40, Cl -35.5, H -1]
JEE Main
Chemistry
Some Basic Concepts of Chemistry
2026
JEE Main 2026 (21 January Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 0.35 mol of H _ 2 gas is evolved.
- B. 7.84 L of H _ 2 gas is evolved.
- C. The limiting reagent is calcium metal.
- D. 33.3 g of CaCl _ 2 is produced.
Answer
D. 33.3 g of CaCl _ 2 is produced.
Step-by-step solution
Reaction: Ca + 2HCl CaCl_2 + H_2 Moles of Ca = 14.0 40 = 0.35 mol. Since HCl is in excess, Ca is limiting. Option (1): H_2 evolved = 0.35 mol Option (2): Volume of H_2 at STP = 0.35 22.4 = 7.84 L Option (3): Ca is limiting reagent Option (4): Mass of CaCl_2 = 0.35 111 = 38.85 g, not 33.3 g Statement (4) is incorrect.
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