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JEE Main Chemistry Structure of Atom 2026 JEE Main 2026 (06 April Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Match the LIST-I with LIST-II List-I Orbital List-II Radial nodes and nodal plane A. 2s I. 1 Radial node + two nodal planes B. 3s II. 1 Radial node + one nodal plane C. 3p III. 2 Radial nodes + No nodal plane D. 4d IV. 1 Radial node + No nodal plane Choose the correct answer from the options given below:

Options

  1. A. A-IV, B-I, C-III, D-II
  2. B. A-IV, B-II, C-III, D-I
  3. C. A-III, B-I, C-IV, D-II
  4. D. A-IV, B-III, C-II, D-I

Answer

D. A-IV, B-III, C-II, D-I

Step-by-step solution

The number of radial nodes is given by the formula n - l - 1. The number of nodal planes (angular nodes) is given by l. For 2s orbital: n = 2, l = 0. Radial nodes = 2 - 0 - 1 = 1. Nodal planes = 0. This matches A with IV. For 3s orbital: n = 3, l = 0. Radial nodes = 3 - 0 - 1 = 2. Nodal planes = 0. This matches B with III. For 3p orbital: n = 3, l = 1. Radial nodes = 3 - 1 - 1 = 1. Nodal planes = 1. This matches C with II. For 4d orbital: n = 4, l = 2. Radial nodes = 4 - 2 - 1 = 1. Nodal planes = 2. This matches D with I. The correct matching is A-IV, B-III, C-II, D-I. Answer: A-IV, B-III, C-II, D-I

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