Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. A. n = 3, l = 2, m = +1 B. n = 4, l = 0, m = 0 C. n = 6, l = 1, m = 0 D. n = 5, l = 1, m = +1 E. n = 2, l = 1, m = +1 Choose the correct answer from the options given below:
D. E < B < A < D < C
The energy of an atomic orbital in a multi-electron atom is determined by the (n + l) rule. Orbitals with a lower value of (n + l) have lower energy. If two orbitals have the same (n + l) value, the one with the lower n value has lower energy. Calculating the (n + l) value for each given orbital: A. n = 3, l = 2 n + l = 5 B. n = 4, l = 0 n + l = 4 C. n = 6, l = 1 n + l = 7 D. n = 5, l = 1 n + l = 6 E. n = 2, l = 1 n + l = 3 Arranging the orbitals in increasing order of their (n + l) values, we get: 3 This corresponds to the order: E Answer: E < B < A < D < C
Related: Chemistry — Structure of Atom · All PYQ Banks