Question
What is the energy (in J atom^ -1 ) required for the following process? Li^ 2+ (g) Li^ 3+ (g) + e^- (Take the ionization energy for the H atom in the ground state as 2.18 10^ -18 J atom^ -1 )
JEE Main
Chemistry
Structure of Atom
2026
JEE Main 2026 (02 April Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 8.72 10^ -18
- B. 1.962 10^ -18
- C. 1.962 10^ -17
- D. 6.54 10^ -17
Answer
C. 1.962 10^ -17
Step-by-step solution
The given process Li^ 2+ (g) Li^ 3+ (g) + e^- represents the ionization of the hydrogen-like ion Li^ 2+ from its ground state. The ionization energy for a hydrogen-like species is given by the formula: IE = IE_ H Z^2 For Li^ 2+ , the atomic number Z = 3. Given the ionization energy of the hydrogen atom IE_ H = 2.18 10^ -18 J atom^ -1 . Substituting the values: IE = 2.18 10^ -18 (3)^2 IE = 2.18 10^ -18 9 IE = 19.62 10^ -18 J atom^ -1 IE = 1.962 10^ -17 J atom^ -1 Answer: 1.962 10^ -17
Related: Chemistry — Structure of Atom · All PYQ Banks