Question
The wave numbers of three spectral lines of H atom are considered. Identify the set of spectral lines belonging to Balmer series. ( R = Rydberg constant)
JEE Main
Chemistry
Structure of Atom
2026
JEE Main 2026 (28 January Shift 1)
JEE Main Chemistry Question (2026) — Solution
Options
- A. 7 R 144 , 3 R 16 , 16 R 255
- B. 5 R 36 , 8 R 9 , 15 R 16
- C. 3 R 4 , 3 R 16 , 7 R 144
- D. 5 R 36 , 3 R 16 , 21 R 100
Answer
D. 5 R 36 , 3 R 16 , 21 R 100
Step-by-step solution
For the Balmer series, transitions end at n=2. Using the Rydberg formula = R ( 1 2^2 - 1 n^2 ) = R ( 1 4 - 1 n^2 ), we calculate wavenumbers for transitions from different upper levels: From n=3: = R ( 1 4 - 1 9 ) = 5R 36 From n=4: = R ( 1 4 - 1 16 ) = 3R 16 From n=5: = R ( 1 4 - 1 25 ) = 21R 100 Option (4) contains exactly these three wavenumbers corresponding to the Balmer series transitions.
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