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JEE Main Chemistry Structure of Atom 2026 JEE Main 2026 (22 January Shift 2)

JEE Main Chemistry Question (2026) — Solution

Question

The energy of first (lowest) Balmer line of H atom is x ~J . The energy (in J) of second Balmer line of H atom is :

Options

  1. A. 1.35 x
  2. B. x^ 2
  3. C. 2 x
  4. D. x 1.35

Answer

A. 1.35 x

Step-by-step solution

First Balmer line: transition n=3 to n=2, energy E_1 = 13.6( 1 4 - 1 9 ) = 13.6 5 36 = x J. Second Balmer line: transition n=4 to n=2, energy E_2 = 13.6( 1 4 - 1 16 ) = 13.6 3 16 J. Ratio: E_2 E_1 = 3 16 5 36 = 3 16 36 5 = 27 20 = 1.35. Thus second Balmer line energy is 1.35x J.

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Related: Chemistry — Structure of Atom · All PYQ Banks