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JEE Main Chemistry Thermodynamics (C) 2026 JEE Main 2026 (24 January Shift 1)

JEE Main Chemistry Question (2026) — Solution

Question

Match the LIST-I with LIST-II \( array |l|l|c|l| List-I & Isothermal process \\ & for ideal gas system & List-II & Work done (V_f > V_i) \\ A. & Reversible expansion & I. & w = 0 \\ B. & Free expansion & II. & w = -nRT V_f V_i \\ C. & Irreversible expansion & III. & w = -p_ ex (V_f - V_i) \\ D. & Irreversible compression & IV. & w = -p_ ex (V_i - V_f) \\ array \) Choose the correct answer from the options given below:

Options

  1. A. A-I, B-III, C-II, D-IV
  2. B. A-II, B-I, C-III, D-IV
  3. C. A-IV, B-I, C-III, D-II
  4. D. A-IV, B-II, C-III, D-I

Answer

B. A-II, B-I, C-III, D-IV

Step-by-step solution

Matching isothermal processes with work expressions: A. Reversible expansion: In a reversible isothermal expansion from V_i to V_f (where V_f > V_i), the gas does work against external pressure equal to the surroundings. The work is w = nRT V_f V_i , matching II. B. Free expansion: The gas expands into a vacuum with no external pressure opposition. No work is done: w = 0, matching I. C. Irreversible expansion: Isothermal expansion from V_i to V_f against constant external pressure p_ ex . Work done is w = -p_ ex (V_f - V_i), matching III. D. Irreversible compression: Isothermal compression from V_i to V_f (where V_f The correct pairings are A-II, B-I, C-III, D-IV.

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