JEE Main Mathematics Question (2026) — Solution

Step-by-step solution

The general term in the expansion of (2x^2 + 1 x )^ 10 is given by: T_ r+1 = ^ 10 C_ r (2x^2)^ 10-r ( 1 x )^r T_ r+1 = ^ 10 C_ r 2^ 10-r x^ 20-2r x^ -r T_ r+1 = ^ 10 C_ r 2^ 10-r x^ 20-3r For the coefficient of x^2, we equate the power of x to 2: 20 - 3r = 2 3r = 18 r = 6 Substituting r = 6 in the coefficient part, we get: Coefficient = ^ 10 C_ 6 2^ 10-6 = ^ 10 C_ 4 2^4 = 10 9 8 7 4 3 2 1 16 = 210 16 = 3360 Answer: 3360