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JEE Main Mathematics Circle 2026 JEE Main 2026 (24 January Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

Let S = \ z C : | z-6 i z-2 i |=1 . and . | z-8+2 i z+2 i |= 3 5 \ . Then _ z ~s |z|^ 2 is equal to

Options

  1. A. 385
  2. B. 398
  3. C. 413
  4. D. 423

Answer

A. 385

Step-by-step solution

Solving | z - 6i z - 2i | = 1 y = 4 .....(1) (where z = x + iy) Now solving | z - 8 + 2i z + 2i | = 3 5 x^2 + y^2 - 25x + 4y + 104 = 0 .....(2) Solving (1) & (2) z = 17 + 4i & 8 + 4i |z|^2 = (17)^2 + (4)^2 + (8)^2 + (4)^2 = 385

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