Question
If z= 3 2 + i 2 , i= -1 , then (z^ 201 -i )^ 8 is equal to
If z= 3 2 + i 2 , i= -1 , then (z^ 201 -i )^ 8 is equal to
B. 256
z = 3 2 + i 2 = e^ i /6 . z^ 201 = e^ i 201 /6 = e^ i 33.5 = e^ i(33 + /2) . Since e^ i 33 = e^ i = -1, we get z^ 201 = -1 e^ i /2 = -i. z^ 201 - i = -i - i = -2i. (z^ 201 - i)^8 = (-2i)^8 = 2^8 i^8 = 256 1 = 256.
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