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JEE Main Mathematics Definite Integration 2026 JEE Main 2026 (28 January Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

Let f be a polynomial function such that f (x^ 2 +1 )=x^ 4 +5 x^ 2 +2, for all x R . Then _ 0 ^ 3 f(x) d x is equal to

Options

  1. A. 5 3
  2. B. 41 3
  3. C. 27 2
  4. D. 33 2

Answer

D. 33 2

Step-by-step solution

Let u = x^2 + 1, then x^2 = u - 1. Substituting into the given condition: f(u) = (u-1)^2 + 5(u-1) + 2 = u^2 - 2u + 1 + 5u - 5 + 2 = u^2 + 3u - 2. Therefore, f(x) = x^2 + 3x - 2. Calculating the integral: _0^3 f(x)dx = _0^3 (x^2 + 3x - 2)dx = [ x^3 3 + 3x^2 2 - 2x ]_0^3 = 9 + 27 2 - 6 = 33 2 .

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