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JEE Main Mathematics Functions 2026 JEE Main 2026 (28 January Shift 2)

JEE Main Mathematics Question (2026) — Solution

Question

The sum of all the elements in the range of f(x)= Sgn ( x)+ Sgn ( x)+ Sgn ( x)+ Sgn ( x), x n 2 , n Z , where Sgn ( t )= \ aligned 1, & if t >0 \\ -1, & if t <0 aligned ., is :

Options

  1. A. 2
  2. B. 0
  3. C. 4
  4. D. -2

Answer

A. 2

Step-by-step solution

x (0, /2) y = 1 + 1 + 1 + 1 = 4 x ( /2, ) y = 1 - 1 - 1 - 1 = -2 x ( , 3 /2) y = -1 - 1 + 1 + 1 = 0 x (3 /2, 2 ) y = -1 + 1 - 1 - 1 = -2 Range of y is \ -2, 0, 4\ Required sum = -2 + 0 + 4 = 2

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