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JEE Main Mathematics Hyperbola 2026 JEE Main 2026 (23 January Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

Let the domain of the function f(x)= _ 3 _ 5 _ 7 (9 x-x^ 2 -13 ) be the interval ( m , n ). Let the hyperbola x^ 2 a ^ 2 - y^ 2 ~b ^ 2 =1 have eccentricity n 3 and the length of the latus rectum 8 ~m 3 . Then b ^ 2 - a ^ 2 is equal to :

Options

  1. A. 7
  2. B. 11
  3. C. 5
  4. D. 9

Answer

A. 7

Step-by-step solution

For f(x) = _3 _5 _7(9x-x^2-13): _7( ) > 0 9x-x^2-13 > 1 (x-2)(x-7) _5( ) > 0 _7(9x-x^2-13) > 1 9x-x^2-13 > 7 (x-4)(x-5) Domain = (4, 5), so m = 4, n = 5. Eccentricity e = n/3 = 5/3, latus rectum = 8m/3 = 32/3. e^2 = 1 + b^2/a^2 b^2/a^2 = 16/9. 2b^2/a = 32/3 32a/9 = 32/3 a = 3, so a^2 = 9, b^2 = 16. b^2 - a^2 = 16 - 9 = 7.

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