Question
If ( ^ -1 (x 2 )) = ( ^ -1 1-x^2 ), x (0,1), then the value of x is :
If ( ^ -1 (x 2 )) = ( ^ -1 1-x^2 ), x (0,1), then the value of x is :
A. 1 2
Let = ^ -1 (x 2 ) = x 2 From the right-angled triangle, = x 2 1+2x^2 Let = ^ -1 1-x^2 = 1-x^2 From the right-angled triangle, = 1 - (1-x^2) = x = = x 1-x^2 Given = , substituting the values: x 2 1+2x^2 = x 1-x^2 Since x (0,1), x 0. Dividing by x and squaring both sides: 2 1+2x^2 = 1 1-x^2 2(1-x^2) = 1+2x^2 2 - 2x^2 = 1 + 2x^2 4x^2 = 1 x^2 = 1 4 Since x (0,1), x = 1 2 Answer: 1 2
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