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JEE Main Mathematics Permutation Combination 2026 JEE Main 2026 (06 April Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

The number of 4-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:

Options

  1. A. 2670
  2. B. 2840
  3. C. 2920
  4. D. 3600

Answer

D. 3600

Step-by-step solution

The given word is INCONSEQUENTIAL. The vowels present in the word are I, O, E, U, A. There are 5 distinct vowels. The consonants present in the word are N, C, S, Q, T, L. There are 6 distinct consonants. We need to form 4-letter words consisting of 2 vowels and 2 consonants without repeating any letter. This means all 4 letters in the formed word must be distinct. Number of ways to select 2 distinct vowels from 5 distinct vowels = ^ 5 C_ 2 = 5 4 2 = 10 Number of ways to select 2 distinct consonants from 6 distinct consonants = ^ 6 C_ 2 = 6 5 2 = 15 Number of ways to arrange the 4 selected letters = 4! = 24 Total number of 4-letter words that can be formed = 10 15 24 = 3600 Answer: 3600

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