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JEE Main Mathematics Permutation Combination 2026 JEE Main 2026 (04 April Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

The number of ways of forming a queue of 4 boys and 3 girls such that all the girls are not together, is:

Options

  1. A. 5040
  2. B. 3050
  3. C. 3410
  4. D. 4320

Answer

D. 4320

Step-by-step solution

Total number of boys = 4 Total number of girls = 3 Total number of children = 7 Total number of ways to arrange 7 children in a queue = 7! = 5040 To find the number of ways where all 3 girls are together, consider the 3 girls as a single unit. Total number of units to arrange = 4 boys + 1 unit of girls = 5 units. Number of ways to arrange these 5 units = 5! = 120 Number of ways to arrange the 3 girls among themselves = 3! = 6 Total number of ways where all girls are together = 5! 3! = 120 6 = 720 Number of ways such that all the girls are not together = Total ways - Ways where all girls are together = 5040 - 720 = 4320 Answer: 4320

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