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JEE Main Mathematics Probability 2026 JEE Main 2026 (24 January Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is

Options

  1. A. 67 10^ 8
  2. B. 7 10^ 7
  3. C. 81 10^ 8
  4. D. 73 10^ 8

Answer

D. 73 10^ 8

Step-by-step solution

Binomial distribution with n=8, p= 1 10 , q= 9 10 . P(X 7) = P(X=7) + P(X=8) P(X=7) = 8 7 ( 1 10 )^7 ( 9 10 ) = 72 10^8 P(X=8) = ( 1 10 )^8 = 1 10^8 P(X 7) = 73 10^8

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