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JEE Main Mathematics Quadratic Equation 2026 JEE Main 2026 (28 January Shift 1)

JEE Main Mathematics Question (2026) — Solution

Question

If , , where < , are the roots of the equation x^ 2 -( +3) x+3=0 such that 1 - 1 = 1 3 , then the sum of all possible values of is

Options

  1. A. 8
  2. B. 6
  3. C. 2
  4. D. 4

Answer

B. 6

Step-by-step solution

+ = +3 , = 3 . 1 - 1 = - = 1 3 , so - = 3 = 1 . ( - )^2 = ( + )^2 - 4 : 1 ^2 = ( +3)^2 ^2 - 12 1 = ( +3)^2 - 12 = ^2 - 6 + 9 ^2 - 6 + 8 = 0 = 2 or = 4. Both values satisfy < (verified). Sum = 2 + 4 = 6.

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