MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The starting material, 2-methylpropan-2-ol, is a tertiary alcohol. On heating with 20\% H_2SO_4 at 363\ K , it undergoes acid-catalyzed dehydration to form an alkene, 2-methylpropene (product A). (CH_3)_3C-OH H^+, (CH_3)_2C=CH_2 + H_2O Product A is 2-methylpropene. When 2-methylpropene is treated with water in the presence of concentrated H_2SO_4 and heat, it undergoes acid-catalyzed hydration. The addition of water follows Markovnikov's rule, proceeding via the formation of a stable tertiary carbocation. (CH_3)_2C=CH_2 + H^+ (CH_3)_3C^+ (CH_3)_3C^+ + H_2O (CH_3)_3C-OH + H^+ The final product B is 2-methylpropan-2-ol, which is commonly known as tert-butyl alcohol. Answer: tert-Butylalcohol