MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

Propyne undergoes hydration in the presence of dilute sulphuric acid and mercuric sulphate according to Markovnikov's rule. The addition of a water molecule to the triple bond initially yields an unstable enol intermediate, prop-1-en-2-ol. CH_3-C CH + H_2O Hg^ 2+ , H^+ CH_3-C(OH)=CH_2 The enol intermediate rapidly undergoes tautomerization to form the more stable keto form, propanone. CH_3-C(OH)=CH_2 CH_3-CO-CH_3 Answer: Propanone