MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

The given reaction is Stephen reduction. Isopropyl cyanide is CH _3- CH ( CH _3)- CN . When isopropyl cyanide is treated with SnCl _2 and HCl , it undergoes reduction to form an imine hydrochloride intermediate (A). CH _3- CH ( CH _3)- CN + 2[ H ] + HCl SnCl _2, HCl CH _3- CH ( CH _3)- CH = NH HCl (A) Acidic hydrolysis of the imine hydrochloride yields the corresponding aldehyde (B). CH _3- CH ( CH _3)- CH = NH HCl + H _2 O H _3 O ^+ CH _3- CH ( CH _3)- CHO + NH _4 Cl The product B is CH _3- CH ( CH _3)- CHO , which is 2-methylpropanal. Answer: 2-Methylpropanal