Question
What is the number of moles of hydrogen atoms needed to obtain one mole ethanamine from acetamide using LiAl H _4 /ether as reducing agent.
What is the number of moles of hydrogen atoms needed to obtain one mole ethanamine from acetamide using LiAl H _4 /ether as reducing agent.
A. 4
The chemical reaction for the reduction of acetamide to ethanamine using LiAlH _4 is: CH _3 CONH _2 + 4[ H ] LiAlH _4/ ether CH _3 CH _2 NH _2 + H _2 O In this process, the carbonyl oxygen is removed as a water molecule, which consumes two hydrogen atoms. The carbonyl carbon is reduced to a methylene group ( CH _2), which consumes another two hydrogen atoms. Thus, a total of 4 moles of hydrogen atoms are required to reduce one mole of acetamide to one mole of ethanamine. Answer: 4
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